UBIFS: remove incorrect index space check
When we report free space to user-space, we should not report 0 if the amount of empty LEBs is too low, because they would be produced by GC when needed. Thus, just call 'ubifs_calc_available()' straight away which would take 'min_idx_lebs' into account anyway. Signed-off-by: Artem Bityutskiy <Artem.Bityutskiy@nokia.com>
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@ -709,24 +709,11 @@ void ubifs_release_dirty_inode_budget(struct ubifs_info *c,
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*/
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*/
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long long ubifs_budg_get_free_space(struct ubifs_info *c)
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long long ubifs_budg_get_free_space(struct ubifs_info *c)
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{
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{
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int min_idx_lebs, rsvd_idx_lebs;
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int min_idx_lebs;
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long long available, outstanding, free;
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long long available, outstanding, free;
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/* Do exactly the same calculations as in 'do_budget_space()' */
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spin_lock(&c->space_lock);
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spin_lock(&c->space_lock);
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min_idx_lebs = ubifs_calc_min_idx_lebs(c);
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min_idx_lebs = ubifs_calc_min_idx_lebs(c);
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if (min_idx_lebs > c->lst.idx_lebs)
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rsvd_idx_lebs = min_idx_lebs - c->lst.idx_lebs;
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else
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rsvd_idx_lebs = 0;
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if (rsvd_idx_lebs > c->lst.empty_lebs + c->freeable_cnt + c->idx_gc_cnt
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- c->lst.taken_empty_lebs) {
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spin_unlock(&c->space_lock);
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return 0;
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}
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outstanding = c->budg_data_growth + c->budg_dd_growth;
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outstanding = c->budg_data_growth + c->budg_dd_growth;
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/*
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/*
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